A) \[16\,\mu C\]
B) \[32\,\mu C\]
C) \[16\,\pi \,\mu C\]
D) \[32\,\pi \,\mu C\]
Correct Answer: B
Solution :
Given, no. of turns \[\operatorname{N}=100\] radius, \[\operatorname{r}=\,\,0.01\,m\] resistance, \[\operatorname{R}=10{{\pi }^{2}}\Omega ,\,\,\,\,n=2\times {{10}^{4}}\] As we know, \[\varepsilon =-N\frac{d\phi }{dt}\] \[\frac{\varepsilon }{R}=-\frac{N}{R}\,\frac{d\phi }{dt}\] \[\Delta I=\,\,-\frac{N}{R}\,\frac{d\phi }{dt}\] \[\frac{\Delta q}{\Delta t}=\,\,-\frac{N}{R}\,\frac{\Delta \phi }{\Delta t}\] \[\Delta q=-\left[ \frac{N}{R}\left( \frac{\Delta \phi }{\Delta t} \right) \right]\Delta t\] ?-? ve sign shows that induced emf opposes the change of flux. \[\Delta q=\left[ {{\mu }_{0}}nN\pi {{r}^{2}}\left( \frac{\Delta i}{\Delta t} \right) \right]\frac{1}{R}\Delta t=\frac{{{\mu }_{0}}nN\pi {{r}^{2}}\Delta i}{R}\] \[\Delta q=\,\,\frac{4\pi \times {{10}^{-7}}\times 100\times 4\times \pi \times {{(0.01)}^{2}}\times 2\times {{10}^{4}}}{10{{\pi }^{2}}}\] \[\Delta q=32\mu C\]
You need to login to perform this action.
You will be redirected in
3 sec
