\[{{H}_{2}}(g)\] \[(1\,atm)\] | \[C{{H}_{3}}COONa\]\[({{10}^{-2}}M)\]\[p{{K}_{a}}\] of \[C{{H}_{3}}COOH=\]\[4.74\] | \[N{{H}_{4}}N{{O}_{3}}\]\[(0.2M)\]\[p{{K}_{a}}\]of \[N{{H}_{4}}OH=\]\[4.74\] | \[{{H}_{2}}(g)\] \[(1\,\,atm)\] | \[Pt\] |
Answer:
0.2
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