A) 3
B) 4
C) 6
D) 8
Correct Answer: B
Solution :
[b] Mass of \[HCl\]acid adsorbed by \[10\text{ }g\]charcoal \[=526.3\times {{10}^{-3}}(0.5-0.4)\times 38\approx 2\] (Mw of \[HCl=38g\,mo{{l}^{-1}}\]) The amount of adsorption \[\frac{x}{m}=\frac{2}{0.5}=4\]You need to login to perform this action.
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