A) \[0\]
B) \[\frac{\pi }{2}\]
C) \[\frac{\pi }{3}\]
D) \[\pi \]
Correct Answer: D
Solution :
[d] Let the angle between \[\vec{q}\] and \[\vec{r}\] be \[\theta \]. \[|\vec{p}+\vec{q}+\vec{r}{{|}^{2}}=1\] \[\Rightarrow \,\,\,\,{{p}^{2}}+{{q}^{2}}+{{r}^{2}}+2\vec{p}.\vec{q}+2\vec{q}+2\vec{q}.\vec{r}+2\vec{p}.\vec{r}=1\] \[\Rightarrow \,\,\,\,\,\,1+1+1+2\vec{q}.\vec{r}=1\] \[\Rightarrow \,\,\,\,\,\,\vec{q}\,.\,\,\vec{r}=-1\] \[\Rightarrow \,\,\,\,\,\,\theta =\pi \]You need to login to perform this action.
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