A) zero
B) E/Atc
C) 2E/Atc
D) E/c
Correct Answer: C
Solution :
Incident momentum, \[\operatorname{p} =\frac{E}{e}\] For perfectly reflecting surface with normal incidence \[\Delta p=2p=\frac{2E}{c}\] \[F=\frac{\Delta p}{\Delta t}=\frac{2E}{ct}\] \[P=\frac{F}{A}=\frac{2E}{ct\,A}\]You need to login to perform this action.
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