A) \[v\sqrt{\frac{2h}{g}}\]
B) \[2v\sqrt{\frac{2h}{g}}\]
C) \[4v\sqrt{\frac{2h}{g}}\]
D) \[3v\sqrt{\frac{2h}{g}}\]
Correct Answer: D
Solution :
[d] Solve in the reference frame fixed to the wall. Before collision, velocity of ball = 3v towards it. \[\therefore \] After elastic collision of ball = 3v away from it Time of flight \[=\sqrt{\frac{2h}{g}}\] \[\therefore \] Distance between wall and ball \[=3v\,\sqrt{\frac{2h}{g}}.\]You need to login to perform this action.
You will be redirected in
3 sec