JEE Main & Advanced Sample Paper JEE Main - Mock Test - 22

  • question_answer
    Find the pressure at which temperature attains its maximum value if the relation between pressure and volume for an ideal gas is\[P={{P}_{0}}+(1-\alpha ){{V}^{2}}\]

    A) \[\frac{2{{P}_{0}}}{3}\]                      

    B) \[\frac{{{P}_{0}}}{3}\]

    C) \[{{P}_{0}}\]               

    D) \[\frac{4{{P}_{0}}}{3}\]

    Correct Answer: A

    Solution :

    [a] : Ideal gas equation \[PV=nRT\] \[({{P}_{0}}+(1-\alpha ){{V}^{2}})V=nRT\] \[T=\frac{({{P}_{0}}+(1-\alpha ){{V}^{2}})V}{nR}\] \[\frac{dT}{dV}=\frac{{{P}_{0}}}{nR}+\frac{3{{V}^{2}}(1-\alpha )}{nR}=0\] [For maximum temperature] \[{{P}_{0}}=3(\alpha -1){{V}^{2}}\]or\[{{V}^{2}}=\frac{{{P}_{0}}}{3(\alpha -1)}\] \[\therefore \]\[P={{P}_{0}}+(1-\alpha )\frac{{{P}_{0}}}{3(\alpha -1)}={{P}_{0}}-\frac{{{P}_{0}}}{3}=\frac{2{{P}_{0}}}{3}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner