A) Methyl isocyanide
B) Acetamide
C) Methyl cyanide
D) Nitroethane
Correct Answer: A
Solution :
Reduction of alkyl isocyanides in presence of \[LiAl{{H}_{4}}\]yields secondary amines containing methyl as one of the alkyl group. \[R-N\vec{=}C+4[H]\xrightarrow{LiAl{{H}_{4}}}\underset{2{}^\circ \text{amine}}{\mathop{R-NH-C{{H}_{3}}}}\,\] e.g., \[C{{H}_{3}}-N\vec{=}C+4[H]\xrightarrow{LiAl{{H}_{4}}}\underset{\text{dimethyl}\,\,\text{amine}}{\mathop{C{{H}_{3}}-NH-C{{H}_{3}}}}\,\]whereas, alkyl cyanides give \[1{}^\circ \] amine on reduction.
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