A) \[5\times {{10}^{-3}}\]
B) \[4\times {{10}^{-3}}\]
C) \[6\times {{10}^{-3}}\]
D) \[3\times {{10}^{-3}}\]
Correct Answer: B
Solution :
Mole of \[220\,mg\]of \[C{{O}_{2}}=\frac{220\times {{10}^{-3}}}{44}\] \[=5\times {{10}^{-3}}\]moles; Moles of \[C{{O}_{2}},\] removed are \[=\frac{6\times {{10}^{20}}}{6\times {{10}^{23}}}={{10}^{-3}}moles\] Remaining moles of \[C{{O}_{2}}=[5\times {{10}^{-3}}-{{10}^{-3}}]\] \[=4\times {{10}^{-3}}\,moles\]
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