JEE Main & Advanced Sample Paper JEE Main - Mock Test - 20

  • question_answer
    The polymerisation of propene to linear polypropene is represented by the reaction Where n has large integral value, the average enthalpies of bond dissociation for \[(C=C)\] and \[(C-C)\] at 298 K are \[+590\] and\[+331\,kJmo{{l}^{-1}}\]. The enthalpy of polymerisation is\[-360\,kJ\,mo{{l}^{-1}}\]. Find the value of n.

    A) 5          

    B)                    10                    

    C) 15                    

    D)        20

    Correct Answer: A

    Solution :

    [a] Energy released = Energy due to formation of two single bonds \[=2\times 331=661\,\,kJmo{{l}^{-1}}\]of propene \[\Delta H\]polymerisation / mol \[=590-662=-72\text{ }kJ\text{ }mo{{l}^{-1}}\] \[\Delta H\]polymerisation/mol \[=-72\times n=-360\] \[n=5\]


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