A) Acetic acid
B) Acetamide
C) Methyl cyanide
D) Acetic anhydrides
Correct Answer: B
Solution :
Methyl cyanide on treatment with cone. \[HCl\] give acetamide. \[\underset{Acetonitri\,ie}{\mathop{C{{H}_{3}}C\equiv N}}\,\xrightarrow{Conc.\,HCl}\underset{Acetamide}{\mathop{C{{H}_{3}}CON{{H}_{2}}}}\,\]You need to login to perform this action.
You will be redirected in
3 sec