A) \[{{10}^{2}}\]
B) \[{{10}^{4}}\]
C) 10
D) \[{{10}^{3}}\]
Correct Answer: D
Solution :
Molarity\[=0.01M;\]Resistance \[=40\,ohm;\] |
Cell constant \[\left( \frac{l}{A} \right)=0.4c{{m}^{-1}}\] |
Specific conductivity \[(k)=\frac{cell\,\,\text{constant}}{\text{resistance}}\]\[=\frac{0.4}{40}=0.01\,oh{{m}^{-1}}c{{m}^{-1}}\] |
Molar conductance \[({{\wedge }_{m}})=\frac{1000k}{Molarity}\]\[=\frac{1000\times 0.01}{.01}={{10}^{3}}oh{{m}^{-1}}c{{m}^{2}}mo{{l}^{-1}}\] |
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