A) \[\frac{1}{3}(6\hat{i}+13\hat{j}+18\hat{k})\]
B) \[\frac{2}{3}(6\hat{i}+12\hat{j}-8\hat{k})\]
C) \[\frac{1}{3}(-6\hat{i}-8\hat{j}-9\hat{k})\]
D) \[\frac{2}{3}(-6\hat{i}-12\hat{j}+8\hat{k})\]
Correct Answer: A
Solution :
Let O be the origin and the bisector of \[\angle A\]meets BC at D. Then \[\frac{BD}{DC}=\frac{AB}{AC}\] and position vector of D is given byYou need to login to perform this action.
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