2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main - Mock Test - 18

  • question_answer
    Given vertices \[A(1,1),\] \[B(4,-2)\] and \[C(5,5)\] of a triangle, then the equation of the perpendicular dropped from C to the interior bisector of the angle A is

    A) \[y-5=0\]           

    B)   \[x-5=0\]

    C) \[y+5=0\]           

    D)   \[x+5=0\]

    Correct Answer: B

    Solution :

    The internal bisector of the angle A will divide the opposite side BC at D in the ratio of arms of the angle i.e.  \[AB=3\sqrt{2}\]and \[AC=4\sqrt{2}\]. Hence by ratio formula the point D is \[\left( \frac{31}{7},1 \right)\]. Slope of AD is 0. \[\therefore \] slope of a line perpendicular to AD is \[\infty \]. Equation of line through C perpendicular to this bisector is \[\frac{y-5}{x-5}=m=\infty \] \[\therefore \,\,x-5=0.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner