question_answer

In the following reactions A, B, C and D are, respectively, \[\underset{(blue)}{\mathop{CuS{{O}_{4}}.5{{H}_{2}}O}}\,\underset{(bluish\,\,white)}{\mathop{\xrightarrow{100{}^\circ C}A\xrightarrow{230{}^\circ C}}}\,B\underset{(Black)}{\mathop{\xrightarrow{800{}^\circ C}C+D}}\,+\frac{1}{2}{{O}_{2}}\]

A)                                                                                           A - \[CuS{{O}_{4}}.4{{H}_{2}}O\]                                B - \[CuS{{O}_{4}}\]   C - \[CuO\]        D - \[S{{O}_{3}}\]

B) A - \[CuS{{O}_{4}}.2{{H}_{2}}O\]                             B - \[CuS{{O}_{4}}.{{H}_{2}}O\]    C - \[CuS{{O}_{4}}\]                         D - \[CuO\]

C) A - \[CuS{{O}_{4}}.3{{H}_{2}}O\]                             B - \[CuS{{O}_{4}}.\]\[2{{H}_{2}}O\]         C - \[CuO\]                      D - \[S{{O}_{2}}\]

D) A - \[CuS{{O}_{4}}.{{H}_{2}}O\]                               B - \[CuO\]    C - \[S{{O}_{3}}\]        D - \[Cu{{O}_{2}}\]

Correct Answer: A

Solution :

[a]