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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 17

  • question_answer
    An oscillator is producing FM waves of frequency \[2\text{ }kHz\]with a variation of\[10\text{ }kHz\]. What is the modulating index?

    A) \[0.20\]             

    B)        \[5.0\]    

    C) \[0.67\]             

    D)        \[1.5\]

    Correct Answer: B

    Solution :

    The formula for modulating index is given by \[{{m}_{f}}=\frac{\delta }{{{v}_{m}}}=\frac{Frequency\,\,deviation}{Modulating\,\,frequency}=\frac{10\times {{10}^{3}}}{2\times {{10}^{3}}}=5\]


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