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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 13

  • question_answer
    A white solid (X) on heating evolves \[C{{O}_{2}}\]and gives a white residue (Y) which is soluble in water. (Y) also gives\[C{{O}_{2}}\]when treated with dilute acid. (X) and (Y) are respectively

    A) \[N{{a}_{2}}C{{O}_{3}}\]and\[NaHC{{O}_{3}}\]

    B) \[NaHC{{O}_{3}}\]and\[N{{a}_{2}}C{{O}_{3}}\]

    C) \[CaC{{O}_{3}}\]and\[CaHC{{O}_{3}}\]

    D) \[CaHC{{O}_{3}}\]and\[CaC{{O}_{3}}\]

    Correct Answer: B

    Solution :

    [b]: \[\underset{(X)}{\mathop{2NaHC{{O}_{3}}}}\,\xrightarrow[{}]{\Delta }\underset{white\,residue,\,so\operatorname{lub}le\,in\,\,water}{\mathop{\underset{(Y)}{\mathop{N{{a}_{2}}C{{O}_{3}}}}\,+C{{O}_{2}}+{{H}_{2}}O}}\,\] \[\underset{(Y)}{\mathop{N{{a}_{2}}C{{O}_{3}}}}\,+\underset{(dil.)}{\mathop{2HCl}}\,\xrightarrow[{}]{{}}2NaCl+C{{O}_{2}}+{{H}_{2}}O\]


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