JEE Main & Advanced Sample Paper JEE Main - Mock Test - 10

  • question_answer
    If a, b, c are in A.P., then \[\frac{{{(a-c)}^{2}}}{({{b}^{2}}-ac)}=\]

    A) 1         

    B) 2     

    C) 3         

    D) 4

    Correct Answer: D

    Solution :

    [d]: Given, a, b, c are in \[A.P.\Rightarrow 2b=a+c\] So,\[\frac{{{(a-c)}^{2}}}{({{b}^{2}}-ac)}=\frac{{{(a-c)}^{2}}}{\left\{ {{\left( \frac{a+c}{2} \right)}^{2}}-ac \right\}}\] \[=\frac{{{(a-c)}^{2}}4}{[{{a}^{2}}+{{c}^{2}}+2ac-4ac]}=\frac{4{{(a-c)}^{2}}}{{{(a-c)}^{2}}}=4\]


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