A) \[0\,V\]
B) \[1.5\,V\]
C) \[3\,V\]
D) \[2\,V\]
Correct Answer: A
Solution :
[a] Redrawing the given circuit \[I=\frac{6}{{{R}_{eq}}},\,{{R}_{eq}}=\frac{40}{3}\Omega \] \[I=\frac{9}{20}A\] \[{{I}_{(5,\,\,15)}}=\frac{3}{10}A;\] \[{{I}_{(10,30)}}=\frac{3}{20}A\] \[{{V}_{across\,\,15}}=15\times \frac{3}{10}=4.5V\] \[{{V}_{across\,\,30}}=30\times \frac{3}{20}=\frac{9}{2}=4.5V\] \[{{V}_{BD}}=0V\]You need to login to perform this action.
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