A) Rs.14280
B) Rs.12040
C) Rs.10040
D) Rs.4080
E) Rs.16250
Correct Answer: C
Solution :
Let his monthly income be Rs. x. He spends on food \[=x\times \frac{25}{100}=Rs.\,\frac{x}{4}\] \[\therefore \]Remaining amount \[=x-\frac{x}{4}=Rs.\,\frac{3x}{4}\] Again, he spends on rent\[=\frac{3x}{4}\times \frac{15}{100}=Rs.\,\frac{9x}{80}\] \[\therefore \]Remaining amount\[=\frac{3x}{4}-\frac{9x}{80}\] \[=\frac{60x-9x}{80}=Rs.\,\frac{51x}{80}\] Now, \[\frac{51x}{80}=Rs.\,25602\] \[\therefore \]\[x=25602\times \frac{80}{51}=Rs.\,40160\] The amount he spent on food \[=40160\times \frac{25}{100}=Rs.\,10040\] Method II. Monthly income \[=25602\left( \frac{100}{100-25} \right)\left( \frac{100}{100-15} \right)\] \[=25602\left( \frac{100}{75} \right)\left( \frac{100}{85} \right)\] \[=25602\left( \frac{4}{3} \right)\left( \frac{20}{17} \right)=40160\] \[\therefore \]Exp on food \[=25%\] of 40160 =\[\frac{40160}{4}\]\[=Rs.\,10040\]
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