question_answer

Hydrogen sulphide \[({{H}_{2}}S)\] is a strong reducing agent. Which of the following reactions shows its reducing action -

A)  \[Cd{{(N{{O}_{3}})}_{2}}+{{H}_{2}}S\xrightarrow{{}}CdS+2HN{{O}_{3}}\]

B)  \[CuS{{O}_{4}}+{{H}_{2}}S\xrightarrow{{}}CuS+{{H}_{2}}S{{O}_{4}}\]

C)  \[2FeC{{I}_{3}}+{{H}_{2}}S\xrightarrow{{}}2FeC{{I}_{2}}+2HCI+S\]

D)  \[Pb{{(N{{O}_{3}})}_{2}}+{{H}_{2}}S\xrightarrow{{}}PbS+2C{{H}_{3}}COOH\]

Correct Answer: C

Solution :

[c] In the given reaction \[{{H}_{2}}S\] is undergoing oxidation, hence behave as reducing agent.