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Railways Reasoning Calendar Sample Paper Clock and Calendar Sample Test Paper-11

  • question_answer
    What was the day of the week on 17th June, 1998?

    A)  Monday           

    B)  Tuesday

    C)  Wednesday      

    D)  Thursday

    Correct Answer: C

    Solution :

    [c] 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998) Odd days in 1600 years = 0 Odd days in 300 years \[=(5\times 3)\equiv 1\] 97 years has 24 leap year + 73 ordinary years. Number of odd days in 97 years \[=(24\times 2+73)=121\] = 2 odd days. Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days = 24 weeks = 0 odd day Total number of odd days = (0 + 1 + 2 + 0) = 3 Given day is Wednesday.


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