A) 10%
B) 25%
C) 12%
D) 20%
Correct Answer: D
Solution :
\[A=P\,{{\left( 1+\frac{r}{100} \right)}^{3}}\] \[\therefore \] \[20736=12000\,{{\left( 1+\frac{r}{100} \right)}^{3}}\] \[\Rightarrow \] \[\frac{20736}{12000}=\,{{\left( 1+\frac{r}{100} \right)}^{3}}\] \[\Rightarrow \] \[\frac{1728}{1000}=\,{{\left( 1+\frac{r}{100} \right)}^{3}}\] \[\Rightarrow \] \[{{\left( \frac{12}{10} \right)}^{3}}=\,{{\left( 1+\frac{r}{100} \right)}^{3}}\] \[\Rightarrow \] \[{{\left( 1+\frac{2}{10} \right)}^{3}}=\,{{\left( 1+\frac{r}{100} \right)}^{3}}\] \[\Rightarrow \] \[{{\left( 1+\frac{20}{100} \right)}^{3}}={{\left( 1+\frac{r}{100} \right)}^{3}}\] \[\therefore \] r = 20%
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