question_answer

A keto ester (X) with molecular formula \[{{C}_{6}}{{H}_{10}}{{O}_{3}}\] on treatment with NaOH and \[{{l}_{2}}\] does not give iodoform but on boiling with dilute KOH gives a compound (Y) with molecular formula \[{{C}_{4}}{{H}_{5}}{{O}_{3}}\]which upon acidification followed by heating under goes decarboxylation to give acetone. The keto ester (X) is

A)  \[C{{H}_{3}}COC{{H}_{2}}C{{H}_{2}}COOC{{H}_{3}}\]

B)  \[C{{H}_{3}}COC{{H}_{2}}COO{{C}_{2}}{{H}_{5}}\]

C)  \[C{{H}_{3}}C{{H}_{2}}OC{{H}_{2}}COOC{{H}_{3}}\]          

D)  \[C{{H}_{3}}COCH(C{{H}_{3}})COOC{{H}_{3}}\]