question_answer

A solution contains \[P{{b}^{2+}}\] and \[F{{e}^{2+}}\] ions. To it some quantity of Fe and Pb is added. Then \[[E_{F{{e}^{2+}}\left| Fe \right.}^{{}^\circ }=-0.44V,E_{P{{b}^{2}}\left| Pb \right.}^{{}^\circ }=-0.126V]\]

A)  Concentration of \[P{{b}^{2+}}\] ions will remain unaffected

B)  Concentration of \[P{{b}^{2+}}\] ions will increase

C)  Concentration of \[F{{e}^{2+}}\] ions will increase

D)  Concentration of \[F{{e}^{2+}}\] ions will decrease.