question_answer

One mole of an organic compound consumed 3 moles of \[Hl{{O}_{4}}\] during oxidation to give 2 moles of methanoic acid and 2 moles of methanal respectively. The organic compound is

A)  \[C{{H}_{2}}OH{{\left( CHOH \right)}_{3}}C{{H}_{2}}OH\]

B)  \[C{{H}_{2}}OH\left( CHOH \right)C{{H}_{2}}OC{{H}_{3}}\]

C)  \[H{{O}_{2}}C{{(CHOH)}_{2}}C{{O}_{2}}H\]

D)  \[C{{H}_{2}}OH{{\left( CHOH \right)}_{2}}C{{H}_{2}}OH\]