A) Different stresses and strains
B) The same stress and strain
C) The same strain but different stresses
D) The same stress but different strains
Correct Answer: D
Solution :
\[\text{Stress}=\frac{\text{Force}}{\text{area}}\]. In the present case, force applied and area of cross-section of wires are same, therefore stress has to be the same. \[\text{Strain}=\frac{\text{Stress}}{Y}\] Since the Young?s modulus of steel wire is greater than the copper wire, therefore, strain in case of steel wire is less than that in case of copper wire.
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