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JEE Main & Advanced Physics Elasticity Question Bank Youngs Modulus and Breaking Stress

  • question_answer
    In steel, the Young's modulus and the strain at the breaking point are \[2\times {{10}^{11}}\,N{{m}^{-2}}\] and 0.15 respectively. The stress at the breaking point for steel is therefore                                                [MP PET 1990; MP PMT 1992; DPMT 2001]

    A)                 \[1.33\times {{10}^{11}}\,N{{m}^{-2}}\]  

    B)                 \[1.33\times {{10}^{12}}\,N{{m}^{-2}}\]

    C)                 \[7.5\times {{10}^{-13}}\,N{{m}^{-2}}\]   

    D)                 \[3\times {{10}^{10}}\,N{{m}^{-2}}\]

    Correct Answer: D

    Solution :

        Breaking stress = strain × Young's modulus             \[=0.15\times 2{{\times }^{11}}=3\times {{10}^{10}}\ N{{m}^{-2}}\]


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