A) 2 : 1
B) 1 : 4
C) 1 : 8
D) 8 : 1
Correct Answer: C
Solution :
\[l=\frac{FL}{AY}\Rightarrow l\propto \frac{L}{{{d}^{2}}}\]Þ\[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{{{L}_{1}}}{{{L}_{2}}}\times {{\left( \frac{{{d}_{2}}}{{{d}_{1}}} \right)}^{2}}\]\[=\frac{1}{2}\times {{\left( \frac{1}{2} \right)}^{2}}=\frac{1}{8}\]
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