A) \[2.35\times {{10}^{12}}\,N/{{m}^{2}}\]
B) \[1.35\times {{10}^{10}}\,N/{{m}^{2}}\]
C) \[13.5\times {{10}^{11}}\,N/{{m}^{2}}\]
D) \[23.5\times {{10}^{9}}\,N/{{m}^{2}}\]
Correct Answer: A
Solution :
\[F=2000N,\ L=6m,\ l=0.5\ cm,A={{10}^{-6}}{{m}^{2}}\] \[Y=\frac{FL}{Al}=\frac{2000\times 6}{{{10}^{-6}}\times 0.5\times {{10}^{-2}}}=2.35\times {{10}^{12}}\ N/{{m}^{2}}\]
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