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JEE Main & Advanced Physics Elasticity Question Bank Youngs Modulus and Breaking Stress

  • question_answer
    The temperature of a wire of length 1 metre and area of cross-section \[1\,c{{m}^{2}}\] is increased from 0°C to 100°C. If the rod is not allowed to increase in length, the force required will be \[(\alpha ={{10}^{-5}}/{}^\circ C\] and \[Y={{10}^{11}}\,N/{{m}^{2}})\] [NCERT 1976; CPMT 1982, 91]

    A)                 \[{{10}^{3}}N\]

    B)                 \[{{10}^{4}}N\]

    C)                 \[{{10}^{5}}N\]

    D)                 \[{{10}^{9}}N\]

    Correct Answer: B

    Solution :

        \[F=\]force developed\[=YA\alpha (\Delta \theta )\]             \[={{10}^{11}}\times {{10}^{-4}}\times {{10}^{-5}}\times 100={{10}^{4}}N\]


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