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JEE Main & Advanced Physics Elasticity Question Bank Youngs Modulus and Breaking Stress

  • question_answer
    The Young's modulus of a rubber string 8 cm long and density \[1.5\,kg/{{m}^{3}}\] is \[5\times {{10}^{8}}\,N/{{m}^{2}}\], is suspended on the ceiling in a room. The increase in length due to its own weight will be                               [AIIMS 1986]

    A)                 \[9.6\times {{10}^{-5}}\,m\]            

    B)                 \[9.6\times {{10}^{-11}}\,m\]

    C)                 \[9.6\times {{10}^{-3}}\,m\]

    D)                             9.6 m

    Correct Answer: B

    Solution :

        \[l=\frac{{{L}^{2}}dg}{2Y}=\frac{{{(8\times {{10}^{-2}})}^{2}}\times 1.5\times 9.8}{2\times 5\times {{10}^{8}}}\]\[=9.6\times {{10}^{-11}}m\]


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