A) \[15\times {{10}^{4}}m\]
B) \[7.5\times {{10}^{4}}m\]
C) \[12\times {{10}^{4}}m\]
D) \[25\times {{10}^{4}}m\]
Correct Answer: A
Solution :
\[l=\frac{{{L}^{2}}dg}{2Y}=\frac{{{(10)}^{2}}\times 1500\times 10}{2\times 5\times {{10}^{8}}}=15\times {{10}^{-4}}m\]
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