A) \[2\times {{10}^{12}}N\]
B) \[2\times {{10}^{11}}N\]
C) \[2\times {{10}^{10}}N\]
D) \[2\times {{10}^{6}}N\]
Correct Answer: D
Solution :
When the length of wire is doubled then \[l=L\] and strain = 1 \ Y = strain =\[\frac{F}{A}\] Force = Y × A \[=2\times {{10}^{11}}\times 0.1\times {{10}^{-4}}\]\[=2\times {{10}^{6}}N\]
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