A) \[2.33\times {{10}^{5}}\,N/{{m}^{2}}\]
B) \[23.3\times {{10}^{10}}\,N/{{m}^{2}}\]
C) \[233\times {{10}^{10}}\,N/{{m}^{2}}\]
D) \[2.33\times {{10}^{10}}\,N/{{m}^{2}}\]
Correct Answer: D
Solution :
\[Y=\frac{k}{{{r}_{0}}}=\frac{7}{3\times {{10}^{-10}}}=2.33\times {{10}^{10}}N/{{m}^{2}}\]
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