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JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Young's Double Slit Experiment and Biprism

  • question_answer
    In Young?s double slit experiment, distance between two sources is 0.1 mm. The distance of screen from the sources is 20 cm. Wavelength of light used is 5460 Å. Then angular position of the first dark fringe is  [DCE 2002]

    A)            0.08°                                        

    B)            0.16°

    C)            0.20°                                        

    D)            0.313°

    Correct Answer: D

    Solution :

                       Angular position of first dark fringe                    \[\theta =\frac{\lambda }{d}=\frac{5460\times {{10}^{-10}}}{0.1\times {{10}^{-3}}}\times \frac{180}{\pi }\] (in degree)            = 0.313°                                  


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