A) 0.75
B) 1.5
C) 3.0
D) 4.5
Correct Answer: B
Solution :
For dark fringe at P \[{{S}_{1}}P-{{S}_{2}}P=\Delta =(2n-1)\lambda /2\] Here n =3 and l = 6000 So, \[\Delta =\frac{5\lambda }{2}=5\times \frac{6000}{2}=15000{AA}=1.5\ micron\]
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