A) 0.11o
B) 0.15o
C) 0.22o
D) 0.30o
Correct Answer: B
Solution :
Angular fringe width \[\theta =\frac{\lambda }{d}\Rightarrow \theta \propto \lambda \] \[{{\lambda }_{w}}=\frac{{{\lambda }_{a}}}{{{\mu }_{w}}}\] So \[{{\theta }_{w}}=\frac{{{\theta }_{\text{air}}}}{{{\mu }_{\text{w}}}}\] \[=\frac{0.20}{\frac{4}{3}}=0.15{}^\circ \]
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