A) \[\frac{xd}{L}\]
B) \[\frac{xL}{d}\]
C) \[\frac{Ld}{x}\]
D) \[\frac{1}{Ldx}\]
Correct Answer: A
Solution :
We know that fringe width \[\beta =\frac{D\lambda }{d}\] \[\therefore x=\frac{L\lambda }{d}\Rightarrow \lambda =\frac{xd}{L}\]
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