A) 11.25 kW
B) 21.25 kW
C) 31.25 kW
D) 41.25 kW
Correct Answer: C
Solution :
We know, \[P=\frac{W}{t}\] her, the work done in accelerating the car (W) = Increase in KE \[\therefore P=\frac{\frac{1}{2}m{{v}^{2}}-\frac{1}{2}m{{u}^{2}}}{t}=31.25\,kW\]
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