Answer:
(a) The resistance offered by the block, \[F=\frac{1}{2}\frac{M{{V}^{2}}}{x}\] (b) We know that, \[\frac{{{V}^{2}}}{x}=con\tan t\Rightarrow \frac{V_{1}^{2}}{{{x}_{1}}}=\frac{V_{2}^{2}}{{{x}_{2}}}\]
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