question_answer

A body of mass 10 kg is falling freely from a height of 2 m. What is the loss of PE as it reaches the ground. (Take\[\text{g}=\text{9}.\text{7 m}/{{\text{s}}^{\text{2}}}\]).

Answer:

\[m=kg;\,\,h=2m;\,\,g=9.8\,\,m/{{s}^{2}};\,Loss\,\,of\,\,P.E.=?\] Loss of P.E. = work done by the weight in falling \[=mgh=10\times 9.8\times 2=196\,\,J\]