question_answer

A force of 5 N acting on a body at an angle of\[\text{3}0{}^\circ \]with horizontal direction displaces it horizontally through a distance of 6 m. Calculate the work done.

Answer:

\[F=5N;\,\,S=6m;\,\,\theta =300;\,\,Work\,done=W=?\] We know that,\[W=FS\,\,\cos \theta =5\times 6\times \cos \,\,30=\] \[30\frac{\sqrt{3}}{2}=15\sqrt{3}J.\]