Answer:
\[m=10\,kg\] \[u=-19.6\,m/s\] \[{{h}_{\max }}=?\] \[PE=?\] \[PE=mg\,\,{{h}_{\max }}=\frac{10\times 9.8\times 19.6\times 19.6}{2\times 9.8}\] \[=192.8\,J\]
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