question_answer

A 20 kg ball is thrown upwards with a speed of 6 m/s. Find its potential energy when it reaches the highest point. Also, find the maximum height it reaches (\[\text{g}=\text{9}.\text{8 m}{{\text{s}}^{-\text{2}}}\])

Answer:

\[m=20kg\] \[v=6m/{{s}^{2}}\] \[PE=?\] \[h=?\] \[{{h}_{\max }}=\frac{{{V}^{2}}}{2g}=\frac{6\times 6}{2\times 9.8}=1.8m\] \[PE=mgh=20\times 9.8\times 1.8=352.8\,J\]