question_answer

If a servant lifts \[10\,{{m}^{3}}\] of liquid from a tank, which is at a depth of 40m. If the work done by him is 1600 J, then find the density of the liquid (take \[\text{g}=\text{1}0\text{m}{{\text{s}}^{-\text{2}}}\])

Answer:

Volume \[(v)=10\,{{m}^{3}}\] depth \[(h)=40\,m\] Work \[(w)=1600\,J\] Density of liquid(d) = ? \[g=10\,m/{{s}^{2}}\] \[W=mgh\]                         ????.(1) \[\Rightarrow W=v\times d\times g\times h(\because m=vd)\] \[\Rightarrow d=\frac{1600}{10\times 10\times 40}=0.4\,kg/{{m}^{3}}\]