Answer:
\[KE=\frac{{{P}^{2}}}{2m}\] \[\Rightarrow P\propto \sqrt{KE}\] \[{{P}_{2}}={{P}_{1}}\sqrt{\frac{2KE}{KE}}=\sqrt{2}{{P}_{1}}\] \[\Rightarrow {{P}_{2}}=\sqrt{2}{{P}_{1}}\]
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