question_answer

When the mass and velocity of the body are doubled, what happens to its kinetic energy.

Answer:

\[{{m}^{2}}=2m\] \[{{V}_{2}}=2V\] \[K{{E}_{2}}=\_\_\_\_\_\_K{{E}_{1}}\] \[K{{E}_{2}}=\frac{1}{2}{{m}_{2}}V_{2}^{2}=\frac{1}{2}(2m){{(2V)}^{2}}\]                                                 \[=\frac{1}{2}\times 2m\times 4{{V}^{2}}\]                                                 \[=\left( \frac{1}{2}m{{v}^{2}} \right)8\] \[\Rightarrow K{{E}_{2}}=8K{{E}_{1}}\]