A) \[\frac{1}{4}\]
B) \[\frac{1}{8}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{16}\]
Correct Answer: A
Solution :
Work done \[=F\times s\] \[=(10000\times 9.8)\times 100\] \[=98\times {{10}^{5}}\] joule Power \[=\frac{w}{t}=\frac{90\times {{10}^{5}}}{60\times 60}watts\] Now, \[%=\frac{Power\,\,used\,\,to\,\,lift\,\,load}{Total\,\,power}\times 100\] \[\therefore \] \[80=\frac{98\times {{10}^{5}}}{60\times 60}\times \frac{1}{P}\times 100\] \[\Rightarrow \] \[P=\mathbf{3403}\,\,\mathbf{watts}\]
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