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JEE Main & Advanced Physics Elasticity Question Bank Work Done in Stretching a Wire

  • question_answer
    A 5 metre long wire is fixed to the ceiling. A weight of 10 kg is hung at the lower end and is 1 metre above the floor. The wire was elongated by 1 mm. The energy stored in the wire due to stretching is    [MP PET 1989]

    A) Zero       

    B)                 0.05 joule

    C)                 100 joule

    D)                             500 joule

    Correct Answer: B

    Solution :

    \[W=\frac{1}{2}\times F\times l=\frac{1}{2}mgl\]                  \[=\frac{1}{2}\times 10\times 10\times 1\times {{10}^{-1}}=0.05\ J\]


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